sum of the digits in given number using C and Python

//Program to print the sum of digits -of any number using for loop

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int n,sum=0,rem;
    printf ("Enter the number ") ;
    scanf ("%d",&n) ;
    for( ;n>0;n/=10)
    {
        rem=n%10; /*taking last digit of number*/
        sum+=rem;
    }
    printf("Sum of digits = %d\n",sum) ;
    //printf("Hello world!\n");
    return 0;
}


program2:
#include<stdio.h>

int sum(int n);
void main()
{
    int num;
    printf ("Enter the number ") ;
    scanf("%d",&num) ;
    printf("Sum of digits of %d is %d\n", num, sum(num));
}
int sum (int n)
{
    int i, sum=0, rem;
    while(n>0)
    {
        rem=n%10;
        sum+=rem;
        n/=10;

    }
    return(sum);
/*rem takes the value of last digit*/
/*skips the last, digi t of number*/
}

output:

enter the number:12

sum of the digits of the 12 is 3

3

PYTHON code:

def main():

sum1=rem=0

n=int(input("enter the number"))

for i in range(n):

if n>0:

rem=n%10

sum1=sum1+rem

n=n//10

print(sum1)

if __name__ == '__main__':

main()

output:

enter the number:264

output:10